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CGP EDU Academic Team
Published on: September 12, 2026
The coordinates of a moving particle at any time are given by \(x \quad \alpha^{2}\) and y = bt^2 . The speed of the particle at any moment is
Text Solution
Verified by ExpertsThe correct answer is:
D
Velocity along X -axis \(V_c = -\frac{dx}{dt} - 2\pi\)
Velocity along Y -axis \(v_y = -\frac{dy}{dt} - 2\alpha y\)
Magnitude of velocity of the particle,
\(v = \sqrt{v_{x}^{2} + v_{r}^{2}} = 2r \sqrt{b^{2} + b'^{2}}\)
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